SQL ERROR: query=( SELECT 'common' AS book_type, pbs.book_section_id, pbs.snippet, b.id AS book_id, b.name AS book_name, b.year AS book_year, b.series AS book_series, b.link as book_link, b.litres_link, ba.id AS author_id, ba.name AS author_name, ba.link as author_link, bst.pid as pid, bs.link as section_link FROM kartaslov.phrases p JOIN kartaslov.phrase_book_section pbs ON pbs.phrase_id = p.id AND pbs.book_type = 'common' JOIN kartaslov.books b ON b.id = pbs.book_id JOIN kartaslov.book_authors ba ON ba.id = b.author_id JOIN kartaslov.book_section_text bst ON bst.id = pbs.book_section_text_id JOIN kartaslov.book_sections bs ON bs.id = bst.book_section_id WHERE p.phrase = ? LIMIT 0, 3 ) UNION ALL ( SELECT 'classic' AS book_type, pbs.book_section_id, pbs.snippet, cb.id AS book_id, cb.name AS book_name, cb.year AS book_year, cb.series AS book_series, cb.link as book_link, NULL AS litres_link, cba.id AS author_id, cba.name AS author_name, cba.link AS author_link, cbst.pid as pid, cbs.link as section_link FROM kartaslov.phrases p JOIN kartaslov.phrase_book_section pbs ON pbs.phrase_id = p.id AND pbs.book_type = 'classic' JOIN kartaslov.classic_books cb ON cb.id = pbs.book_id JOIN kartaslov.classic_book_authors cba ON cba.id = cb.author_id JOIN kartaslov.classic_book_section_text cbst ON cbst.id = pbs.book_section_text_id JOIN kartaslov.classic_book_sections cbs ON cbs.id = cbst.book_section_id WHERE p.phrase = ? LIMIT 0, 3 ); err=Unknown column 'pbs.book_section_id' in 'SELECT' SQL_ERR
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| 1 | brainly.com | /question/62407248?s... | |
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[FREE] Simplify the expression
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4 июн. 2025 г. — Apply the power of a power rule |
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| 2 | www.chegg.com | /homework-help/quest... | |
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Solved Follow the instructions below. Write (b4)2 without
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26 апр. 2023 г. — Follow the instructions below. Write (b4)2 without exponents. (b4)2= Fill in the blank. ( b4)2=b . Not the question you're looking for? |
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| 3 | www.reddit.com | /r/askmath/comments/... | |
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I have a test for IBEW can't figure this out and it's driving me ...
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There's is no ambiguity. 1/2(b-4) means everything in () halved. 1/2b -4 is (1/2)/b -4. b/2 -4 is intended but whoever designed this was drunk. |
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| 4 | www.mathway.com | /ru/popular-problems... | |
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Упростить (b^4)^2
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Применим правило степени и перемножим показатели, (am)n=amn ( a m ) n = a m n . b4 ⋅ 2 b 4 ⋅ 2 . Этап 2 . Умножим 4 4 на 2 2 . b 8 b 8. ( b4 ) 2 ( b 4 ) 2 ... |
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| 5 | www.tiger-algebra.com | /drill/(b-4)2/ | |
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Solve Simplification or other simple results (b-4)2 ...
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Equations |
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| 6 | znanija.com | /task/24951151 | |
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сколько будет а в 4 степень + б в4 степени
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16 авг. 2017 г. — 1 - 4 классы. answer. ответ дан. Сколько будет а в 4 степень + б в4 степени. 2 . Посмотреть ответы. Разблокированный значок показывает как сапог ... |
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| 7 | uchi.ru | /otvety/questions/ka... | |
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как решить ? Найди значение выражения
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28 нояб. 2022 г. — (8/a – 5/ b ) = (8 * b – 5 * a) / (a * b ); Тогда |
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| 8 | www.php.net | /manual/en/language.... | |
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Bitwise - Manual
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Right shifts have copies of the sign bit shifted in on the left , meaning the sign of an operand is preserved. Use parentheses to ensure the desired precedence. |
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| 9 | www.wolframalpha.com | /examples/mathematic... | |
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Wolfram|Alpha Examples
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Interactive algebra calculators for solving equations, polynomials, rational functions, simplification, vectors, matrices, linear algebra, quaternions, ... |
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