SQL ERROR: query=( SELECT 'common' AS book_type, pbs.book_section_id, pbs.snippet, b.id AS book_id, b.name AS book_name, b.year AS book_year, b.series AS book_series, b.link as book_link, b.litres_link, ba.id AS author_id, ba.name AS author_name, ba.link as author_link, bst.pid as pid, bs.link as section_link FROM kartaslov.phrases p JOIN kartaslov.phrase_book_section pbs ON pbs.phrase_id = p.id AND pbs.book_type = 'common' JOIN kartaslov.books b ON b.id = pbs.book_id JOIN kartaslov.book_authors ba ON ba.id = b.author_id JOIN kartaslov.book_section_text bst ON bst.id = pbs.book_section_text_id JOIN kartaslov.book_sections bs ON bs.id = bst.book_section_id WHERE p.phrase = ? LIMIT 0, 3 ) UNION ALL ( SELECT 'classic' AS book_type, pbs.book_section_id, pbs.snippet, cb.id AS book_id, cb.name AS book_name, cb.year AS book_year, cb.series AS book_series, cb.link as book_link, NULL AS litres_link, cba.id AS author_id, cba.name AS author_name, cba.link AS author_link, cbst.pid as pid, cbs.link as section_link FROM kartaslov.phrases p JOIN kartaslov.phrase_book_section pbs ON pbs.phrase_id = p.id AND pbs.book_type = 'classic' JOIN kartaslov.classic_books cb ON cb.id = pbs.book_id JOIN kartaslov.classic_book_authors cba ON cba.id = cb.author_id JOIN kartaslov.classic_book_section_text cbst ON cbst.id = pbs.book_section_text_id JOIN kartaslov.classic_book_sections cbs ON cbs.id = cbst.book_section_id WHERE p.phrase = ? LIMIT 0, 3 ); err=Unknown column 'pbs.book_section_id' in 'SELECT' SQL_ERR
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| 1 | znanija.com | /task/34529293 | |
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x×10-2=8.Решить уравнение
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9 мар. 2020 г. — Ответ |
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| 3 | uchi.ru | /otvety/questions/re... | |
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Решить уравнение x+10=2x+8
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13 июл. 2018 г. — 2 + 10 = 2 * 2 + 8 ;. 12 = 4 + 8 ;. 12 = 12. Уравнение решено верно. Ответ |
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| 4 | www.mathway.com | /popular-problems/Al... | |
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Solve for x (x+10)^2-8=8
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Take the specified root of both sides of the equation to eliminate the exponent on the left side. x+10=±√16 x + 10 = ± 16. Step 4. Simplify ±√16 ± 16 . |
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| 5 | otvet.mail.ru | /question/80826620 | |
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Сколько корней имеет уравнение x10=2& - vlad_bondarev_80
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9 окт. 2012 г. — Корень 1. x = 2 , 8 . Это в твоей записи. А вот так X ^ 10 =28, корней 10 штук. Из них только 2 действительных. |
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| 7 | t-kom.tvel.ru | /products/detail.php... | |
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ТПК-20-10/2-П
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Коммутатор ТПК-20- 10 / 2 -П предназначен для применения в сетях промышленных предприятий и поддерживает расширенные функции управления и безопасности. |
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| 8 | krone.ru | /catalog/plinty/plin... | |
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Titre
Плинт с нормально замкнутыми контактами LSA ...
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Характеристики плинта Krone LSA-PROFIL 2 / 8 х 3 a-b-s |
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