www.esaral.com

Registriran

Snimka zaslona web stranice

Datum ažuriranja analize stranice: 2026/06/05 01:07:52

Zadnji datum ažuriranja Whois: 2026/07/01 15:49:11

Status domene

Registriran

Plaćeno do

14.02.2031

Dostupno od

16.03.2031

SEO rezultat

81.51%

119

Postignut rezultat

146

Maksimalni rezultat

Glavne informacije

ℹ️

Titula: eSaral - JEE | NEET | Class 8-10 Exam Prep App

Opis: eSaral is the Best edTech platform of India which offers comprehensive education for JEE, NEET, class 8-10 exams with India’s Best IITian and Doctor faculties.

Ključne riječi: nepoznato

Kodiranje stranice: utf-8

Veličina datoteke stranice: 195 KB

Informacije o poslužitelju

🖥️

IP: 143.244.132.123

Mjesto: India,IN,Bengaluru,560100,12.9753,77.591,Asia/Kolkata

Http poslužitelj: nginx/1.22.0 (ubuntu)

Kodiranje: utf-8

Popis meta oznaka

🏷️

property: og:title content: eSaral - JEE | NEET | Class 8-10 Exam Prep App
property: twitter:title content: eSaral - JEE | NEET | Class 8-10 Exam Prep App
name: description content: eSaral is the Best edTech platform of India which offers comprehensive education for JEE, NEET, class 8-10 exams with India’s Best IITian and Doctor faculties.
property: og:description content: eSaral is the Best edTech platform of India which offers comprehensive education for JEE, NEET, class 8-10 exams with India’s Best IITian and Doctor faculties.
property: twitter:description content: eSaral is the Best edTech platform of India which offers comprehensive education for JEE, NEET, class 8-10 exams with India’s Best IITian and Doctor faculties.
property: og:type content: website
property: og:image content:
property: og:url content: /
property: twitter:card content: eSaral
property: twitter:url content: /
property: twitter:image content:
name: description content: eSaral is the Best edTech platform of India which offers comprehensive education for JEE, NEET, class 8-10 exams with India’s Best IITian and Doctor faculties.
equiv: Content-Type content: text/html; charset=utf-8
name: HandheldFriendly content: true
name: viewport content: width=device-width, initial-scale=1
charset: UTF-8
name: viewport content: width=device-width, initial-scale=1.0, maximum-scale=1.0, user-scalable=no

Interne veze

🔗

Vanjske veze

🌐

Whois informacije

📄

domain_name: esaral.com

update_date: 2025-11-07T06:30:41Z

update_time: 1762497041

creation_date: 2018-02-14T04:44:17Z

creation_time: 1518583457

expiration_date: 2031-02-14T04:44:17Z

Whois neobrađeni podaci

📋

            Domain Name: ESARAL.COM
Registrar: GoDaddy.com, LLC
Domain Status: client delete prohibited
Domain Status: client renew prohibited
Domain Status: client transfer prohibited
Domain Status: client update prohibited
Creation Date: 2018-02-14T04:44:17Z
Registry Expiry Date: 2031-02-14T04:44:17Z
Updated Date: 2025-11-07T06:30:41Z
Name Server: LINA.NS.CLOUDFLARE.COM
Name Server: RAJEEV.NS.CLOUDFLARE.COM
REGISTRAR Contact: GoDaddy.com, LLC
>>> Last update of RDAP database: 2026-07-01T15:49:11Z

Robots.txt

🤖

			User-agent: *
Disallow: /cgi-bin/
Disallow: /control-panel-2023/
Sitemap: https://www.esaral.com/sitemap.xml

SEO revizija

🔍

Tehnički SEO

✓

Šifra odgovora

200

Status 200 OK - stranica se ispravno učitava.

✓

Kodiranje znakova

Page: utf-8, Header: utf-8

Konzistentno kodiranje znakova između HTML-a i zaglavlja.

✓

Veličina stranice

199775 bytes

Veličina stranice prihvatljiva za brzo učitavanje.

Resursi

124 total

Previše resursa. Optimizirajte i kombinirajte datoteke za bolju izvedbu.

✓

Hreflang oznake

1 hreflang tags

Hreflang oznake pronađene za višejezični SEO.

✓

Robots.txt

Exists

Datoteka robots.txt pronađena.

✓

Sitemap

Declared in robots.txt

Sitemap deklariran u robots.txt.

✓

HTTPS

Yes

Sigurna HTTPS veza omogućena.

✓

Kompresija

gzip

Gzip ili Zstd kompresija omogućena za brže učitavanje.

Predmemoriranje

Not set

Dodajte zaglavlja kontrole predmemorije kako biste poboljšali brzinu učitavanja za ponovne posjetitelje.

✓

Brzina stranice

3.23 ms

Izvrsna brzina učitavanja.

On-Page SEO

✓

Titula

eSaral - JEE | NEET | Class 8-10 Exam Prep App

Dobra duljina naslova (30-60 znakova).

✓

Meta opis

eSaral is the Best edTech platform of India which offers comprehensive education for JEE, NEET, class 8-10 exams with India’s Best IITian and Doctor faculties. Lenght:159

Dobra duljina meta opisa (100-160 znakova).

✓

H1 naslov

1 found - "India's Most Trusted & Loved Institue"

Dobro - pronađen je jedan H1 naslov.

✓

Broj riječi

2196

Sadržaj vrlo opsežan. Razmotrite razbijanje na više stranica ako je predugo.

Kanonska oznaka

Dodajte kanonsku oznaku kako biste spriječili probleme s dvostrukim sadržajem.

Duplikat Meta

{"description":2,"viewport":2}

Uklonite dvostruke meta oznake kako biste izbjegli sukobe.

✓

Ključne riječi

Meta ključne riječi nisu obavezne (ne koriste ih glavne tražilice).

Sadržaj i UX

✓

Jezik

en-in

Jezični atribut pravilno postavljen.

Slike

86 total, 9 missing ALT

Dodajte ALT tekst slikama za pristupačnost i SEO.

✓

Viewport

width=device-width, initial-scale=1

Meta oznaka Viewport ispravno postavljena za mobilne uređaje.

✓

Otvori grafikon

All OG tags present.

Prisutne sve bitne OpenGraph oznake.

✓

Strukturirani podaci

2 JSON-LD scripts

Pronađeni su strukturirani podaci (JSON-LD).

Pozicije u Google

Fraze za pretraživanje - Google

🔍

Položaj	Fraza	Stranica	Isječak
4	angle aob 90 circ	/q/in-the-given-figu...	In the given figure, ∠AOB = 90° and ∠ABC = 30°. 4 янв. 2023 г. — Question: In the given figure, AOB = 90 and ABC= 30. Then, CAO= ?(a) 30(b) 45(c) 60(d) 90 Solution: (c) 60We have:AOB = 2ACB $\Rightarrow ...
4	mathrm ab mathrm cb	/q/in-figure-if-math...	In figure, if $\mathrm{LM} 24 июн. 2023 г. — Solution: In $\triangle \ mathrm {ACB}$ (see figure), $\ mathrm {LM} \\| \ mathrm { CB }$ (Given) $\Rightarrow \frac{A M}{M B}=\frac{A L}{L C}$ .
5	angle mathrm c 90 circ	/q/in-right-angled-t...	In right-angled triangle ABC is which ∠C = 90°, 4 янв. 2023 г. — Solution: $\triangle \mathrm{ABC}$ is a right-angled triangle with $\ angle \mathrm{C}=90^{\circ }$. D is the mid-point of $\mathrm{BC}$.
5	angle mathrm abc	/q/in-the-following-...	In the following figure, ABC is a right triangle right angled at ... 24 июн. 2023 г. — (i) We know that each angle of a square is $90^{\circ}$. Hence, $\angle \ m athrm{ABM}=\angle \mathrm{DBC}=90^{\circ}$ $\Rightarrow \angle A B M ...
5	x 2y 3 0	/q/draw-the-graph-of...	Draw the graph of the equation x + 2y – 3 = 0. 4 янв. 2023 г. — Plot the points ( 3 , 0 ) ,(1,1) and (-1,2) on the graph paper. Join the points and extend the line in both the directions. The line segment is the required graph ...
6	angle oab	/q/in-figure-1-o-is-...	Find ∠AOC \| ∠OAB=40°, ∠OCB=30° \| Circle Theorem ... 1 июл. 2026 г. — ∠AOC = 140°. Using isosceles triangles OAB and OCB (radii are equal), we get ∠OBA = 40° and ∠OBC = 30°. So ∠ABC = 70°. By the central angle ...
8	решить уравнение x 2y 3 0	/q/draw-the-graph-of...	Draw the graph of the equation x + 2y – 3 = 0. 4 янв. 2023 г. — Solution: Given equation: x + 2y - 3 = 0 . Or, x + 2y = 3 . When y = 0 , x + 0 = 3 ⇒ x = 3 . When y = 1, x + 2 = 3 ⇒ x = 3 -2 = 1
8	ac cd mathrm ab mathrm bd	/q/in-the-following-...	In the following figure, if AC = BD, then prove that AB = CD. Solution: From the figure, it can be observed that $\ mathrm { AC }=\ mathrm { AB }+\ mathrm {BC}$ $ B D =B C+ C D $ It is given that $ A C = B D $
8	write about schools	/english/essay-on-my...	Essay on My School Life – 100 to 500 Words for Students 2 июн. 2026 г. — Education has been the core of my school life . I have gained knowledge across various subjects. I explored my interests through extracurricular ...
8	my best teacher	/english/essay-on-my...	Essay on My Favourite Teacher in English (150, 200, 300 ... 30 мая 2026 г. — My favourite teacher is Mrs. Sadhna Kausik , and she teaches Science. She lives near our school and is not just my favourite — she is widely ...

Pozicije u Yandex

Fraze za pretraživanje - Yandex

🔍

Položaj	Fraza	Stranica	Isječak
9	9 mathrm 2	/binomial-theorem-je...	Binomial Theorem - JEE Main Previous Year Question with... ... mathrm {C}_{50}( 2 \sqrt{\ mathrm {x}})^{50}$ add both equations and put $\ mathrm {x}=1$ $\Rightarrow \ mathrm {sum}$ of coefficients of integral powers of $\ mathrm ...

Dodatne usluge

💎

www.esaral.com

www.esaral.com Snimka zaslona web stranice

Glavne informacije

Informacije o poslužitelju

Popis meta oznaka

Interne veze

Vanjske veze

Whois informacije

Whois neobrađeni podaci

Robots.txt

SEO revizija

Tehnički SEO

On-Page SEO

Sadržaj i UX

Pozicije u Google

Fraze za pretraživanje - Google

Pozicije u Yandex

Fraze za pretraživanje - Yandex

Dodatne usluge

Plaćanje uspješno!

Plaćanje usluge

Plaćanje

Prijavite se na svoj račun

Napravi račun

Kontrolni kod

Završite registraciju u Telegramu

Potvrdite svoju e-poštu