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update_date: 07-Apr-2026
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This Registry database contains ONLY .EDU domains. The data in the EDUCAUSE Whois database is provided by EDUCAUSE for information purposes in order to assist in the process of obtaining information about or related to .edu domain registration records. The EDUCAUSE Whois database is authoritative for the .EDU domain. A Web interface for the .EDU EDUCAUSE Whois Server is available at: http://whois.educause.edu By submitting a Whois query, you agree that this information will not be used to allow, enable, or otherwise support the transmission of unsolicited commercial advertising or solicitations via e-mail. The use of electronic processes to harvest information from this server is generally prohibited except as reasonably necessary to register or modify .edu domain names. ------------------------------------------------------------- Domain Name: UPENN.EDU Registrant: University of Pennsylvania ISC Technology Services 3401 Walnut Street Suite 221A Philadelphia, PA 19104-6228 USA Administrative Contact: Domain Admin University of Pennsylvania ISC Technology Services 3401 Walnut Street Suite 221A Philadelphia, PA 19104-6228 USA +1.2158982883 [email protected] Technical Contact: Domain Admin University of Pennsylvania ISC Technology Services 3401 Walnut Street Suite 221A Philadelphia, PA 19104-6228 USA +1.2158982883 [email protected] Name Servers: ADNS6.UPENN.EDU DNS1.UDEL.EDU ADNS1.NNN.UPENN.EDU ADNS4.UPENN.EDU ADNS2.NNN.UPENN.EDU DNS2.UDEL.EDU ADNS5.UPENN.EDU ADNS3.NNN.UPENN.EDU Domain record activated: 02-Jun-1986 Domain record last updated: 07-Apr-2026 Domain expires: 31-Jul-2027
The first few of these are easy -- 1 + 3 + 5 + 7 = 16, 1 + 3 + 5 + 7 + 9 = 25 - and you may begin to notice the pattern that the sum is always a square number.
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/~chai/370f09/370hwf...
SOLUTION: Each element of Q8 generates a (cyclic) subgroup of Q8 , so in addition to Q8 and {1}, we have subgroups generated by elements such as i,j,k, and −1.
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/~rimmer/math103/not...
Let and be differentiable functions and let be a constant. f x. g x k. 1. Constant function. y k. = 2. Linear function.
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/~ancoop/103/interac...
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/~vedranso/math425_h...
Solve the equation: (1 + x2) ux + uy = 0. Describe its characteristic curves. Solution: We use the method of characteristics. Let us first rewrite the equation ...